Optimal. Leaf size=89 \[ \frac{\left (a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{2 d}-\frac{a b \cot (c+d x)}{d}-\frac{\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^2}{2 d}-2 a b x+\frac{3 b^2 \cos (c+d x)}{2 d} \]
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Rubi [A] time = 0.305784, antiderivative size = 89, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.222, Rules used = {2889, 3048, 3031, 3023, 2735, 3770} \[ \frac{\left (a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{2 d}-\frac{a b \cot (c+d x)}{d}-\frac{\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^2}{2 d}-2 a b x+\frac{3 b^2 \cos (c+d x)}{2 d} \]
Antiderivative was successfully verified.
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Rule 2889
Rule 3048
Rule 3031
Rule 3023
Rule 2735
Rule 3770
Rubi steps
\begin{align*} \int \cot ^2(c+d x) \csc (c+d x) (a+b \sin (c+d x))^2 \, dx &=\int \csc ^3(c+d x) (a+b \sin (c+d x))^2 \left (1-\sin ^2(c+d x)\right ) \, dx\\ &=-\frac{\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^2}{2 d}+\frac{1}{2} \int \csc ^2(c+d x) (a+b \sin (c+d x)) \left (2 b-a \sin (c+d x)-3 b \sin ^2(c+d x)\right ) \, dx\\ &=-\frac{a b \cot (c+d x)}{d}-\frac{\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^2}{2 d}-\frac{1}{2} \int \csc (c+d x) \left (a^2-2 b^2+4 a b \sin (c+d x)+3 b^2 \sin ^2(c+d x)\right ) \, dx\\ &=\frac{3 b^2 \cos (c+d x)}{2 d}-\frac{a b \cot (c+d x)}{d}-\frac{\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^2}{2 d}-\frac{1}{2} \int \csc (c+d x) \left (a^2-2 b^2+4 a b \sin (c+d x)\right ) \, dx\\ &=-2 a b x+\frac{3 b^2 \cos (c+d x)}{2 d}-\frac{a b \cot (c+d x)}{d}-\frac{\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^2}{2 d}-\frac{1}{2} \left (a^2-2 b^2\right ) \int \csc (c+d x) \, dx\\ &=-2 a b x+\frac{\left (a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{2 d}+\frac{3 b^2 \cos (c+d x)}{2 d}-\frac{a b \cot (c+d x)}{d}-\frac{\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^2}{2 d}\\ \end{align*}
Mathematica [A] time = 0.900336, size = 155, normalized size = 1.74 \[ \frac{a^2 \left (-\csc ^2\left (\frac{1}{2} (c+d x)\right )\right )+a^2 \sec ^2\left (\frac{1}{2} (c+d x)\right )-4 a^2 \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )+4 a^2 \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )+8 a b \tan \left (\frac{1}{2} (c+d x)\right )-8 a b \cot \left (\frac{1}{2} (c+d x)\right )-16 a b c-16 a b d x+8 b^2 \cos (c+d x)+8 b^2 \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )-8 b^2 \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )}{8 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.079, size = 126, normalized size = 1.4 \begin{align*} -{\frac{{a}^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{2\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2}}}-{\frac{{a}^{2}\cos \left ( dx+c \right ) }{2\,d}}-{\frac{{a}^{2}\ln \left ( \csc \left ( dx+c \right ) -\cot \left ( dx+c \right ) \right ) }{2\,d}}-2\,abx-2\,{\frac{ab\cot \left ( dx+c \right ) }{d}}-2\,{\frac{abc}{d}}+{\frac{{b}^{2}\cos \left ( dx+c \right ) }{d}}+{\frac{{b}^{2}\ln \left ( \csc \left ( dx+c \right ) -\cot \left ( dx+c \right ) \right ) }{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.68321, size = 139, normalized size = 1.56 \begin{align*} -\frac{8 \,{\left (d x + c + \frac{1}{\tan \left (d x + c\right )}\right )} a b - a^{2}{\left (\frac{2 \, \cos \left (d x + c\right )}{\cos \left (d x + c\right )^{2} - 1} + \log \left (\cos \left (d x + c\right ) + 1\right ) - \log \left (\cos \left (d x + c\right ) - 1\right )\right )} - 2 \, b^{2}{\left (2 \, \cos \left (d x + c\right ) - \log \left (\cos \left (d x + c\right ) + 1\right ) + \log \left (\cos \left (d x + c\right ) - 1\right )\right )}}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.44467, size = 414, normalized size = 4.65 \begin{align*} -\frac{8 \, a b d x \cos \left (d x + c\right )^{2} - 4 \, b^{2} \cos \left (d x + c\right )^{3} - 8 \, a b d x - 8 \, a b \cos \left (d x + c\right ) \sin \left (d x + c\right ) - 2 \,{\left (a^{2} - 2 \, b^{2}\right )} \cos \left (d x + c\right ) -{\left ({\left (a^{2} - 2 \, b^{2}\right )} \cos \left (d x + c\right )^{2} - a^{2} + 2 \, b^{2}\right )} \log \left (\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) +{\left ({\left (a^{2} - 2 \, b^{2}\right )} \cos \left (d x + c\right )^{2} - a^{2} + 2 \, b^{2}\right )} \log \left (-\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right )}{4 \,{\left (d \cos \left (d x + c\right )^{2} - d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.37059, size = 200, normalized size = 2.25 \begin{align*} \frac{a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 16 \,{\left (d x + c\right )} a b + 8 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 4 \,{\left (a^{2} - 2 \, b^{2}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right ) + \frac{16 \, b^{2}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1} + \frac{6 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 12 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 8 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - a^{2}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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